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JEE MAINS 2024
31.01.24 S1
Question
If the wavelength of the first member of Lyman series of hydrogen is λ. The wavelength of the second member will be
Select the correct option:
A
$\frac{27}{32} \lambda$
B
$\frac{32}{27} \lambda$
C
$\frac{27}{5} \lambda$
D
$\frac{5}{27} \lambda$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Sol. $$ \begin{aligned} & \frac{1}{\lambda}=\frac{13.6 \mathrm{z}^2}{\mathrm{hc}}\left[\frac{1}{1^2}-\frac{1}{2^2}\right] \ldots . . \\ & \frac{1}{\lambda^{\prime}}=\frac{13.6 \mathrm{z}^2}{\mathrm{hc}}\left[\frac{1}{1^2}-\frac{1}{3^2}\right] \end{aligned} $$ On dividing (i) \& (ii) $$ \lambda^{\prime}=\frac{27}{32} \lambda $$
Question Tags
JEE Main
Physics
Easy
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