The hydrogen electrode is dipped in a solution of $\mathrm{pH}=3$ at $25^{\circ} \mathrm{C}$. The potential of the electrode will be
$
\begin{gathered}
\times 10^{-2} \mathrm{~V} . \\
\left(\frac{2.303 \mathrm{RT}}{\mathrm{~F}}=0.059 \mathrm{~V}\right)
\end{gathered}
$
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