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JEE MAIN 2025
24-01-2025 SHIFT-1
Question
A force ${\rm{F}} - \alpha + \beta {{\rm{x}}^2}$ acts on an object in the x -direction. The work done by the force is 5 J when the object is displaced by 1 m. If the constant $a = 1\;{\rm{N}}$ then $\beta $ will be
Select the correct option:
A
$12\;{\rm{N}}/{{\rm{m}}^2}$
B
$1.5\;{\rm{N}}/{{\rm{m}}^2}$
C
$8\;{\rm{N}}/{{\rm{m}}^2}$
D
$10\;{\rm{N}}/{{\rm{m}}^2}$
✓ Correct! Well done.
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