Let in a $\Delta ABC$, the length of the side AC be 6, the vertex B be (1, 2, 3) and the vertices A, C lie on the line $\frac{{x - 6}}{3} = \frac{{y - 7}}{2} = \frac{{z - 7}}{{ - 2}}$. Then the area (in sq. units) of $\Delta ABC$ is:
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