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JEE-Main_2024
290124_(S2)
Question
A bob of mass ' $m$ ' is suspended by a light string of length ' $L$ '. It is imparted a minimum horizontal velocity at the lowest point $A$ such that it just completes half circle reaching the top most position B. The ratio of kinetic energies $\frac{(\text { K.E. })_A}{(\text { K.E. })_B}$ is :
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Select the correct option:
A
3 : 2
B
5 : 1
C
2 : 5
D
1 : 5
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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