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JEE MAIN 2025
23-01-2025 SHIFT-2
Question
A plane electromagnetic wave of frequency 20 MHz travels in free space along the +x direction. At a particular point in space and time, the electric field vector of the wave is $\mathrm{E}_{y}=9.3 \mathrm{Vm}^{-1}$. Then, the magnetic field vector of the wave at that point is
Select the correct option:
A
$\mathrm{B}_{\mathrm{z}}=3.1 \times 10^{-8} \mathrm{~T}$
B
$\mathrm{B}_{z}=6.2 \times 10^{-8} \mathrm{~T}$
C
$\mathrm{B}_{z}=9.3 \times 10^{-8} \mathrm{~T}$
D
$B_{z}=1.55 \times 10^{-8} \mathrm{~T}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$E=B C$
$9.3=\mathrm{B} \times 3 \times 10^{8}$
$B=\frac{9.3}{3 \times 10^{8}}=3.1 \times 10^{-8} \mathrm{~T}$
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