An element 'E' has the ionisation enthalpy value of $374\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{ - 1}}$. 'E' reacts with elements A, B, C and D with electron gain enthalpy values of $ - 328, - 349, - 325$ and $ - 295\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{ - 1}}$, respectively. The correct order of the products EA, EB, EC and ED in terms of ionic character is :
Select the correct option:
A
${\rm{ED}} > {\rm{EC}} > {\rm{EB}} > {\rm{EA}}$
B
${\rm{EA}} > {\rm{EB}} > {\rm{EC}} > {\rm{ED}}$
C
${\rm{ED}} > {\rm{EC}} > {\rm{EA}} > {\rm{EB}}$
D
${\rm{EB}} > {\rm{EA}} > {\rm{EC}} > {\rm{ED}}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Difference between I.E. & E.G.E increases, ionic character increases.
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