Butane reacts with oxygen to produce carbon dioxide and water following the equation given below.
If 174.0 kg of butane is mixed with 320.0 kg of , the volume of water formed in liters is_____. (Nearest integer)
[Given : (a) Molar mass of C, H, O are respectively, (b) Density of water
Write Your Answer
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$$
\begin{aligned}
& \mathrm{C}_4 \mathrm{H}_{10}+\frac{13}{2} \mathrm{O}_2 \rightarrow 4 \mathrm{CO}_2+5 \mathrm{H}_2 \mathrm{O} \\
& 3 \times 10^3 10 \times 10^3
\end{aligned}
$$
Moles of $\mathrm{H}_2 \mathrm{O}$ formed $=\mathrm{n}_{\mathrm{H}_2 \mathrm{O}}=5 \times \frac{2}{13} \times 10 \times 10^3$
Then $\mathrm{w}_{\mathrm{H}_2 \mathrm{O}}=\frac{10^5}{13} \times 18$
$$
=1.3846 \times 10^5 \mathrm{~g}
$$
Volume of $\mathrm{H}_2 \mathrm{O}$ will be $=138.46$ litre.
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇
