Iron (III) catalyses the reaction between iodide and persulphate ions, in which
A. $\mathrm{Fe}^{3+}$ oxidises the iodide ion
B. $\mathrm{Fe}^{3+}$ oxidises the persulphate ion
C. $\mathrm{Fe}^{2+}$ reduces the iodide ion
D.$\mathrm{Fe}^{2+}$ reduces the persulphate ion
Choose the most appropriate answer from the options given below:
Select the correct option:
A
B and C only
B
B only
C
A only
D
A and D only
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$$
\begin{aligned}
& 2 \mathrm{Fe}^{3+}+2 \mathrm{I}^{-} \rightarrow 2 \mathrm{Fe}^{2+}+\mathrm{I}_2 \\
& 2 \mathrm{Fe}^{2+}+\mathrm{S}_2 \mathrm{O}_8^{2-} \rightarrow 2 \mathrm{Fe}^{3+}+2 \mathrm{SO}_{14}^{2-}
\end{aligned}
$$
$\mathrm{Fe}^{+3}$ oxidises $\mathrm{I}^{-}$to $\mathrm{I}_2$ and conv ert itself into $\mathrm{Fe}^{+2}$. This $\mathrm{Fe}^{+2}$ reduces $\mathrm{S}_2 \mathrm{O}_8{ }^{2-}$ to $\mathrm{SO}_4{ }^{2-}$ and converts itself into $\mathrm{Fe}^{+3}$.
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