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JEE MAIN
29-01-24 S1
Question
Let $\left(5, \frac{a}{4}\right)$, be the circumcenter of a triangle with vertices $A(a,-2), B(a, 6)$ and $C\left(\frac{a}{4},-2\right)$. Let $\alpha$ denote the circumradius, $\beta$ denote the area and $\gamma$ denote the perimeter of the triangle. Then $\alpha+\beta+\gamma$ is
Select the correct option:
A
60
B
53
C
62
D
30
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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