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JEE MAIN 2025
02-04-2025 SHIFT-1
Question
Moment of inertia of a rod of mass 'M' and length 'L' about an axis passing through its center and normal to its length is '$\alpha$'. Now the rod is cut into two equal parts and these parts are joined symmetrically to form a cross shape. Moment of inertia of cross about an axis passing through its center and normal to plane containing cross is :
Select the correct option:
A
$\alpha /4$
B
$\alpha /2$
C
$\alpha$
D
$\alpha /8$
✓ Correct! Well done.
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