The amphoteric oxide among $\mathrm{V}_{2} \mathrm{O}_{3}, \mathrm{~V}_{2} \mathrm{O}_{4}$ and $\mathrm{V}_{2} \mathrm{O}_{5}$, upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is :
Select the correct option:
A
+7
B
+5
C
+4
D
+3
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\quad \mathrm{V}_{2} \mathrm{O}_{5}+$ alkali $\rightarrow \mathrm{VO}_{4}^{3-}$
In $\mathrm{VO}_{4}^{3-}$ ion, vanadium is in +5 oxidation state
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