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JEE MAIN 2024
04-04-2024 S1
Question
The vertices of a triangle are A(-1,3),B(-2,2) and C(3,-1). A new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is :
Select the correct option:
A
$x-y-(2+\sqrt{2})=0$
B
$-x+y-(2-\sqrt{2})=0$
C
$x+y-(2-\sqrt{2})=0$
D
$x+y+(2-\sqrt{2})=0$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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